14304204022133 has 4 divisors (see below), whose sum is σ = 14304417352428. Its totient is φ = 14303990691840.

The previous prime is 14304204022127. The next prime is 14304204022139. The reversal of 14304204022133 is 33122040240341.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (14304204022127) and next prime (14304204022139).

It can be written as a sum of positive squares in 2 ways, for example, as 12803966097169 + 1500237924964 = 3578263^2 + 1224842^2 .

It is a cyclic number.

It is not a de Polignac number, because 14304204022133 - 2¹² = 14304204018037 is a prime.

It is a super-2 number, since 2×14304204022133² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14304204022096 and 14304204022105.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14304204022139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106564538 + ... + 106698683.

It is an arithmetic number, because the mean of its divisors is an integer number (3576104338107).

Almost surely, 2^{14304204022133} is an apocalyptic number.

It is an amenable number.

14304204022133 is a deficient number, since it is larger than the sum of its proper divisors (213330295).

14304204022133 is an equidigital number, since it uses as much as digits as its factorization.

14304204022133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 213330294.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 14304204022133 its reverse (33122040240341), we get a palindrome (47426244262474).

The spelling of 14304204022133 in words is "fourteen trillion, three hundred four billion, two hundred four million, twenty-two thousand, one hundred thirty-three".