Base | Representation |
---|---|
bin | 1000010100111001111… |
… | …0110110110101011011 |
3 | 111200020110000001212112 |
4 | 2011032132312311123 |
5 | 4320431430220124 |
6 | 145414435302535 |
7 | 13222633212503 |
oct | 2051636666533 |
9 | 450213001775 |
10 | 143050632539 |
11 | 55738397561 |
12 | 2388344aa4b |
13 | 106498c37c9 |
14 | 6cd0854a03 |
15 | 3ac396790e |
hex | 214e7b6d5b |
143050632539 has 2 divisors, whose sum is σ = 143050632540. Its totient is φ = 143050632538.
The previous prime is 143050632463. The next prime is 143050632541. The reversal of 143050632539 is 935236050341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143050632539 - 216 = 143050567003 is a prime.
Together with 143050632541, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 143050632496 and 143050632505.
It is not a weakly prime, because it can be changed into another prime (143050632239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71525316269 + 71525316270.
It is an arithmetic number, because the mean of its divisors is an integer number (71525316270).
Almost surely, 2143050632539 is an apocalyptic number.
143050632539 is a deficient number, since it is larger than the sum of its proper divisors (1).
143050632539 is an equidigital number, since it uses as much as digits as its factorization.
143050632539 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 291600, while the sum is 41.
The spelling of 143050632539 in words is "one hundred forty-three billion, fifty million, six hundred thirty-two thousand, five hundred thirty-nine".
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