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14305818281 is a prime number
BaseRepresentation
bin11010101001011000…
…10111011010101001
31100220222220212101112
431110230113122221
5213244242141111
610323315200105
71014340310006
oct152454273251
940828825345
1014305818281
116081297017
122932ba6035
13146ca96041
14999d628ad
1558ade0e8b
hex354b176a9

14305818281 has 2 divisors, whose sum is σ = 14305818282. Its totient is φ = 14305818280.

The previous prime is 14305818239. The next prime is 14305818283. The reversal of 14305818281 is 18281850341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11248723600 + 3057094681 = 106060^2 + 55291^2 .

It is a cyclic number.

It is not a de Polignac number, because 14305818281 - 218 = 14305556137 is a prime.

It is a super-3 number, since 3×143058182813 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

Together with 14305818283, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (14305818283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7152909140 + 7152909141.

It is an arithmetic number, because the mean of its divisors is an integer number (7152909141).

Almost surely, 214305818281 is an apocalyptic number.

It is an amenable number.

14305818281 is a deficient number, since it is larger than the sum of its proper divisors (1).

14305818281 is an equidigital number, since it uses as much as digits as its factorization.

14305818281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 61440, while the sum is 41.

The spelling of 14305818281 in words is "fourteen billion, three hundred five million, eight hundred eighteen thousand, two hundred eighty-one".