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14310032204213 is a prime number
BaseRepresentation
bin1101000000111101000001…
…1000101110000110110101
31212200000200202012202111122
43100033100120232012311
53333423421221013323
650233534341113325
73004602636533624
oct320172030560665
955600622182448
1014310032204213
11461793a132449
1217314689b8845
137ca579337365
14376875b176bb
1519c3841cbec8
hexd03d062e1b5

14310032204213 has 2 divisors, whose sum is σ = 14310032204214. Its totient is φ = 14310032204212.

The previous prime is 14310032204173. The next prime is 14310032204269. The reversal of 14310032204213 is 31240223001341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12611071156849 + 1698961047364 = 3551207^2 + 1303442^2 .

It is a cyclic number.

It is not a de Polignac number, because 14310032204213 - 240 = 13210520576437 is a prime.

It is a super-2 number, since 2×143100322042132 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14310032204113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155016102106 + 7155016102107.

It is an arithmetic number, because the mean of its divisors is an integer number (7155016102107).

Almost surely, 214310032204213 is an apocalyptic number.

It is an amenable number.

14310032204213 is a deficient number, since it is larger than the sum of its proper divisors (1).

14310032204213 is an equidigital number, since it uses as much as digits as its factorization.

14310032204213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 14310032204213 its reverse (31240223001341), we get a palindrome (45550255205554).

The spelling of 14310032204213 in words is "fourteen trillion, three hundred ten billion, thirty-two million, two hundred four thousand, two hundred thirteen".