14310034131 has 8 divisors (see below), whose sum is σ = 19909612800. Its totient is φ = 9125239112.

The previous prime is 14310034127. The next prime is 14310034147. The reversal of 14310034131 is 13143001341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14310034131 - 2² = 14310034127 is a prime.

It is a super-2 number, since 2×14310034131² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14310034098 and 14310034107.

It is not an unprimeable number, because it can be changed into a prime (14310034171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 103695831 + ... + 103695968.

It is an arithmetic number, because the mean of its divisors is an integer number (2488701600).

Almost surely, 2^14310034131 is an apocalyptic number.

14310034131 is a deficient number, since it is larger than the sum of its proper divisors (5599578669).

14310034131 is a wasteful number, since it uses less digits than its factorization.

14310034131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 207391825.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 14310034131 its reverse (13143001341), we get a palindrome (27453035472).

The spelling of 14310034131 in words is "fourteen billion, three hundred ten million, thirty-four thousand, one hundred thirty-one".