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1431004423423 = 3581673359351
BaseRepresentation
bin10100110100101110100…
…000101010010011111111
312001210200011021200202111
4110310232200222103333
5141421144113022143
63013221103034451
7205246423622041
oct24645640522377
95053604250674
101431004423423
11501981766523
121b140859ba27
13a4c350c7653
144d3921d3a91
152735504099d
hex14d2e82a4ff

1431004423423 has 8 divisors (see below), whose sum is σ = 1431640750176. Its totient is φ = 1430368236000.

The previous prime is 1431004423411. The next prime is 1431004423487. The reversal of 1431004423423 is 3243244001341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1431004423423 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431004423523) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24081198 + ... + 24140548.

It is an arithmetic number, because the mean of its divisors is an integer number (178955093772).

Almost surely, 21431004423423 is an apocalyptic number.

1431004423423 is a deficient number, since it is larger than the sum of its proper divisors (636326753).

1431004423423 is an equidigital number, since it uses as much as digits as its factorization.

1431004423423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69665.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 1431004423423 its reverse (3243244001341), we get a palindrome (4674248424764).

The spelling of 1431004423423 in words is "one trillion, four hundred thirty-one billion, four million, four hundred twenty-three thousand, four hundred twenty-three".

Divisors: 1 3581 6733 59351 24110873 212535931 399610283 1431004423423