14310133113 has 4 divisors (see below), whose sum is σ = 19080177488. Its totient is φ = 9540088740.

The previous prime is 14310133073. The next prime is 14310133171. The reversal of 14310133113 is 31133101341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 14310133113 - 2¹⁷ = 14310002041 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14310133113.

It is not an unprimeable number, because it can be changed into a prime (14310137113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2385022183 + ... + 2385022188.

It is an arithmetic number, because the mean of its divisors is an integer number (4770044372).

Almost surely, 2^14310133113 is an apocalyptic number.

It is an amenable number.

14310133113 is a deficient number, since it is larger than the sum of its proper divisors (4770044375).

14310133113 is an equidigital number, since it uses as much as digits as its factorization.

14310133113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4770044374.

The product of its (nonzero) digits is 324, while the sum is 21.

Adding to 14310133113 its reverse (31133101341), we get a palindrome (45443234454).

The spelling of 14310133113 in words is "fourteen billion, three hundred ten million, one hundred thirty-three thousand, one hundred thirteen".