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1431020201223 = 32410319790347
BaseRepresentation
bin10100110100101111011…
…100110110010100000111
312001210201020222021211110
4110310233130312110013
5141421212132414343
63013222425140103
7205250005004334
oct24645734662407
95053636867743
101431020201223
1150198a662628
121b141192a633
13a4c38460022
144d39433d98b
152735660a833
hex14d2f736507

1431020201223 has 8 divisors (see below), whose sum is σ = 1908106192768. Its totient is φ = 953973838584.

The previous prime is 1431020201213. The next prime is 1431020201251. The reversal of 1431020201223 is 3221020201341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1431020201223 - 26 = 1431020201159 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1431020201223.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431020201203) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9822865 + ... + 9967482.

It is an arithmetic number, because the mean of its divisors is an integer number (238513274096).

Almost surely, 21431020201223 is an apocalyptic number.

1431020201223 is a deficient number, since it is larger than the sum of its proper divisors (477085991545).

1431020201223 is a wasteful number, since it uses less digits than its factorization.

1431020201223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19814453.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 1431020201223 its reverse (3221020201341), we get a palindrome (4652040402564).

The spelling of 1431020201223 in words is "one trillion, four hundred thirty-one billion, twenty million, two hundred one thousand, two hundred twenty-three".

Divisors: 1 3 24103 72309 19790347 59371041 477006733741 1431020201223