Base | Representation |
---|---|
bin | 11010101001111010… |
… | …01000001001101001 |
3 | 1100221022012002201022 |
4 | 31110331020021221 |
5 | 213301403242301 |
6 | 10323553302225 |
7 | 1014422540165 |
oct | 152475101151 |
9 | 40838162638 |
10 | 14310212201 |
11 | 608381825a |
12 | 2934564975 |
13 | 1470973cac |
14 | 99a787ca5 |
15 | 58b4acd1b |
hex | 354f48269 |
14310212201 has 2 divisors, whose sum is σ = 14310212202. Its totient is φ = 14310212200.
The previous prime is 14310212177. The next prime is 14310212261. The reversal of 14310212201 is 10221201341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14238216976 + 71995225 = 119324^2 + 8485^2 .
It is a cyclic number.
It is not a de Polignac number, because 14310212201 - 222 = 14306017897 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14310212201.
It is not a weakly prime, because it can be changed into another prime (14310212261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155106100 + 7155106101.
It is an arithmetic number, because the mean of its divisors is an integer number (7155106101).
Almost surely, 214310212201 is an apocalyptic number.
It is an amenable number.
14310212201 is a deficient number, since it is larger than the sum of its proper divisors (1).
14310212201 is an equidigital number, since it uses as much as digits as its factorization.
14310212201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 14310212201 its reverse (10221201341), we get a palindrome (24531413542).
The spelling of 14310212201 in words is "fourteen billion, three hundred ten million, two hundred twelve thousand, two hundred one".
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