Base | Representation |
---|---|
bin | 11010101001111010… |
… | …01000001011011101 |
3 | 1100221022012002212121 |
4 | 31110331020023131 |
5 | 213301403243232 |
6 | 10323553302541 |
7 | 1014422540422 |
oct | 152475101335 |
9 | 40838162777 |
10 | 14310212317 |
11 | 6083818355 |
12 | 2934564a51 |
13 | 147097406b |
14 | 99a787d49 |
15 | 58b4acd97 |
hex | 354f482dd |
14310212317 has 2 divisors, whose sum is σ = 14310212318. Its totient is φ = 14310212316.
The previous prime is 14310212261. The next prime is 14310212339. The reversal of 14310212317 is 71321201341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12547136196 + 1763076121 = 112014^2 + 41989^2 .
It is a cyclic number.
It is not a de Polignac number, because 14310212317 - 211 = 14310210269 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14310212291 and 14310212300.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14310212347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155106158 + 7155106159.
It is an arithmetic number, because the mean of its divisors is an integer number (7155106159).
Almost surely, 214310212317 is an apocalyptic number.
It is an amenable number.
14310212317 is a deficient number, since it is larger than the sum of its proper divisors (1).
14310212317 is an equidigital number, since it uses as much as digits as its factorization.
14310212317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 14310212317 its reverse (71321201341), we get a palindrome (85631413658).
The spelling of 14310212317 in words is "fourteen billion, three hundred ten million, two hundred twelve thousand, three hundred seventeen".
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