143102342124035 has 48 divisors (see below), whose sum is σ = 204410481935616. Its totient is φ = 95842602055872.

The previous prime is 143102342123963. The next prime is 143102342124041. The reversal of 143102342124035 is 530421243201341.

It is not a de Polignac number, because 143102342124035 - 2²² = 143102337929731 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (35).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143102342123986 and 143102342124004.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 419406914 + ... + 419747976.

It is an arithmetic number, because the mean of its divisors is an integer number (4258551706992).

Almost surely, 2^{143102342124035} is an apocalyptic number.

143102342124035 is a deficient number, since it is larger than the sum of its proper divisors (61308139811581).

143102342124035 is a wasteful number, since it uses less digits than its factorization.

143102342124035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 380952 (or 380945 counting only the distinct ones).

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 143102342124035 its reverse (530421243201341), we get a palindrome (673523585325376).

The spelling of 143102342124035 in words is "one hundred forty-three trillion, one hundred two billion, three hundred forty-two million, one hundred twenty-four thousand, thirty-five".