Base | Representation |
---|---|
bin | 1101000000111101110011… |
… | …0001100001000111100000 |
3 | 1212200001020020021110112110 |
4 | 3100033130301201013200 |
5 | 3333424332421444300 |
6 | 50234011123355320 |
7 | 3004611042200331 |
oct | 320173461410740 |
9 | 55601206243473 |
10 | 14310240031200 |
11 | 4617a36480993 |
12 | 1731506522b40 |
13 | 7ca5b04020c9 |
14 | 376895576288 |
15 | 19c397580550 |
hex | d03dcc611e0 |
14310240031200 has 216 divisors, whose sum is σ = 48241425429288. Its totient is φ = 3684475074560.
The previous prime is 14310240031193. The next prime is 14310240031237. The reversal of 14310240031200 is 213004201341.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 1526547 + ... + 5563346.
It is an arithmetic number, because the mean of its divisors is an integer number (223339932543).
Almost surely, 214310240031200 is an apocalyptic number.
14310240031200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14310240031200 is an abundant number, since it is smaller than the sum of its proper divisors (33931185398088).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14310240031200 is a wasteful number, since it uses less digits than its factorization.
14310240031200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7089974 (or 7089932 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 14310240031200 its reverse (213004201341), we get a palindrome (14523244232541).
The spelling of 14310240031200 in words is "fourteen trillion, three hundred ten billion, two hundred forty million, thirty-one thousand, two hundred".
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