1431030113 has 4 divisors (see below), whose sum is σ = 1435631808. Its totient is φ = 1426428420.

The previous prime is 1431030109. The next prime is 1431030137. The reversal of 1431030113 is 3110301341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1431030113 - 2² = 1431030109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1431030091 and 1431030100.

It is not an unprimeable number, because it can be changed into a prime (1431030193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2300381 + ... + 2301002.

It is an arithmetic number, because the mean of its divisors is an integer number (358907952).

Almost surely, 2^1431030113 is an apocalyptic number.

It is an amenable number.

1431030113 is a deficient number, since it is larger than the sum of its proper divisors (4601695).

1431030113 is an equidigital number, since it uses as much as digits as its factorization.

1431030113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4601694.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 1431030113 is about 37828.9586560349. The cubic root of 1431030113 is about 1126.8936306856.

Adding to 1431030113 its reverse (3110301341), we get a palindrome (4541331454).

The spelling of 1431030113 in words is "one billion, four hundred thirty-one million, thirty thousand, one hundred thirteen".