14310323042 has 4 divisors (see below), whose sum is σ = 21465484566. Its totient is φ = 7155161520.

The previous prime is 14310323033. The next prime is 14310323047. The reversal of 14310323042 is 24032301341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12591308521 + 1719014521 = 112211^2 + 41461^2 .

It is a super-3 number, since 3×14310323042³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 14310322999 and 14310323017.

It is not an unprimeable number, because it can be changed into a prime (14310323047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3577580759 + ... + 3577580762.

Almost surely, 2^14310323042 is an apocalyptic number.

14310323042 is a deficient number, since it is larger than the sum of its proper divisors (7155161524).

14310323042 is an equidigital number, since it uses as much as digits as its factorization.

14310323042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7155161523.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 14310323042 its reverse (24032301341), we get a palindrome (38342624383).

The spelling of 14310323042 in words is "fourteen billion, three hundred ten million, three hundred twenty-three thousand, forty-two".