Base | Representation |
---|---|
bin | 1000010101000110100… |
… | …0110000100111000110 |
3 | 111200101010121001212211 |
4 | 2011101220300213012 |
5 | 4321034002411014 |
6 | 145424005534034 |
7 | 13224145122403 |
oct | 2052150604706 |
9 | 450333531784 |
10 | 143103560134 |
11 | 55765257877 |
12 | 2389911431a |
13 | 10657865602 |
14 | 6cd78b12aa |
15 | 3ac841ecc4 |
hex | 2151a309c6 |
143103560134 has 4 divisors (see below), whose sum is σ = 214655340204. Its totient is φ = 71551780066.
The previous prime is 143103560129. The next prime is 143103560221. The reversal of 143103560134 is 431065301341.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 143103560096 and 143103560105.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35775890032 + ... + 35775890035.
It is an arithmetic number, because the mean of its divisors is an integer number (53663835051).
Almost surely, 2143103560134 is an apocalyptic number.
143103560134 is a deficient number, since it is larger than the sum of its proper divisors (71551780070).
143103560134 is an equidigital number, since it uses as much as digits as its factorization.
143103560134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71551780069.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 143103560134 its reverse (431065301341), we get a palindrome (574168861475).
The spelling of 143103560134 in words is "one hundred forty-three billion, one hundred three million, five hundred sixty thousand, one hundred thirty-four".
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