143104013317 has 2 divisors, whose sum is σ = 143104013318. Its totient is φ = 143104013316.

The previous prime is 143104013251. The next prime is 143104013347. The reversal of 143104013317 is 713310401341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132438494241 + 10665519076 = 363921^2 + 103274^2 .

It is a cyclic number.

It is not a de Polignac number, because 143104013317 - 2¹¹ = 143104011269 is a prime.

It is a super-2 number, since 2×143104013317² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143104013347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71552006658 + 71552006659.

It is an arithmetic number, because the mean of its divisors is an integer number (71552006659).

Almost surely, 2^143104013317 is an apocalyptic number.

It is an amenable number.

143104013317 is a deficient number, since it is larger than the sum of its proper divisors (1).

143104013317 is an equidigital number, since it uses as much as digits as its factorization.

143104013317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3024, while the sum is 28.

Adding to 143104013317 its reverse (713310401341), we get a palindrome (856414414658).

The spelling of 143104013317 in words is "one hundred forty-three billion, one hundred four million, thirteen thousand, three hundred seventeen".