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143110434331 = 17231707721433
BaseRepresentation
bin1000010101001000001…
…0111110111000011011
3111200101121112022111201
42011102002332320123
54321042232344311
6145424413135031
713224260422654
oct2052202767033
9450347468451
10143110434331
1155769122527
122389b48a477
1310659101497
146cd878052b
153ac8d2b9c1
hex21520bee1b

143110434331 has 16 divisors (see below), whose sum is σ = 158133536064. Its totient is φ = 128822436864.

The previous prime is 143110434329. The next prime is 143110434367. The reversal of 143110434331 is 133434011341.

It is a cyclic number.

It is not a de Polignac number, because 143110434331 - 21 = 143110434329 is a prime.

It is a super-2 number, since 2×1431104343312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 143110434331.

It is not an unprimeable number, because it can be changed into a prime (143110432331) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6666391 + ... + 6687823.

It is an arithmetic number, because the mean of its divisors is an integer number (9883346004).

Almost surely, 2143110434331 is an apocalyptic number.

143110434331 is a deficient number, since it is larger than the sum of its proper divisors (15023101733).

143110434331 is a wasteful number, since it uses less digits than its factorization.

143110434331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38550.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 143110434331 its reverse (133434011341), we get a palindrome (276544445672).

The spelling of 143110434331 in words is "one hundred forty-three billion, one hundred ten million, four hundred thirty-four thousand, three hundred thirty-one".

Divisors: 1 17 23 391 17077 21433 290309 364361 392771 492959 6677107 8380303 366011341 6222192797 8418260843 143110434331