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14311105441 = 39301364141
BaseRepresentation
bin11010101010000001…
…00010001110100001
31100221100212111000021
431111000202032201
5213302120333231
610324024353441
71014433250323
oct152500421641
940840774007
1014311105441
116084278376
122934915881
131470bc7739
1499a93b613
1558b5d7811
hex3550223a1

14311105441 has 4 divisors (see below), whose sum is σ = 14311508884. Its totient is φ = 14310702000.

The previous prime is 14311105423. The next prime is 14311105489. The reversal of 14311105441 is 14450111341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7156483216 + 7154622225 = 84596^2 + 84585^2 .

It is a cyclic number.

It is not a de Polignac number, because 14311105441 - 25 = 14311105409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14311195441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142770 + ... + 221371.

It is an arithmetic number, because the mean of its divisors is an integer number (3577877221).

Almost surely, 214311105441 is an apocalyptic number.

It is an amenable number.

14311105441 is a deficient number, since it is larger than the sum of its proper divisors (403443).

14311105441 is an equidigital number, since it uses as much as digits as its factorization.

14311105441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 403442.

The product of its (nonzero) digits is 960, while the sum is 25.

Adding to 14311105441 its reverse (14450111341), we get a palindrome (28761216782).

The spelling of 14311105441 in words is "fourteen billion, three hundred eleven million, one hundred five thousand, four hundred forty-one".

Divisors: 1 39301 364141 14311105441