Base | Representation |
---|---|
bin | 10100110100110100111… |
… | …000011000011100110011 |
3 | 12001210221121101211201211 |
4 | 110310310320120130303 |
5 | 141421403443230021 |
6 | 3013235441540551 |
7 | 205252162245133 |
oct | 24646470303463 |
9 | 5053847354654 |
10 | 1431111305011 |
11 | 501a27028213 |
12 | 1b1438344757 |
13 | a4c512aa4ab |
14 | 4d3a2496ac3 |
15 | 2735e6043e1 |
hex | 14d34e18733 |
1431111305011 has 2 divisors, whose sum is σ = 1431111305012. Its totient is φ = 1431111305010.
The previous prime is 1431111304969. The next prime is 1431111305053. The reversal of 1431111305011 is 1105031111341.
It is a balanced prime because it is at equal distance from previous prime (1431111304969) and next prime (1431111305053).
It is a cyclic number.
It is not a de Polignac number, because 1431111305011 - 215 = 1431111272243 is a prime.
It is not a weakly prime, because it can be changed into another prime (1431111305081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715555652505 + 715555652506.
It is an arithmetic number, because the mean of its divisors is an integer number (715555652506).
Almost surely, 21431111305011 is an apocalyptic number.
1431111305011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1431111305011 is an equidigital number, since it uses as much as digits as its factorization.
1431111305011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 180, while the sum is 22.
Adding to 1431111305011 its reverse (1105031111341), we get a palindrome (2536142416352).
The spelling of 1431111305011 in words is "one trillion, four hundred thirty-one billion, one hundred eleven million, three hundred five thousand, eleven".
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