14311115771 has 2 divisors, whose sum is σ = 14311115772. Its totient is φ = 14311115770.

The previous prime is 14311115759. The next prime is 14311115773. The reversal of 14311115771 is 17751111341.

It is a strong prime.

It is an emirp because it is prime and its reverse (17751111341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14311115771 - 2²² = 14306921467 is a prime.

It is a super-2 number, since 2×14311115771² (a number of 21 digits) contains 22 as substring.

Together with 14311115773, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14311115773) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155557885 + 7155557886.

It is an arithmetic number, because the mean of its divisors is an integer number (7155557886).

Almost surely, 2^14311115771 is an apocalyptic number.

14311115771 is a deficient number, since it is larger than the sum of its proper divisors (1).

14311115771 is an equidigital number, since it uses as much as digits as its factorization.

14311115771 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2940, while the sum is 32.

The spelling of 14311115771 in words is "fourteen billion, three hundred eleven million, one hundred fifteen thousand, seven hundred seventy-one".