14311130411 has 2 divisors, whose sum is σ = 14311130412. Its totient is φ = 14311130410.

The previous prime is 14311130333. The next prime is 14311130413. The reversal of 14311130411 is 11403111341.

It is a strong prime.

It is an emirp because it is prime and its reverse (11403111341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14311130411 - 2¹⁰ = 14311129387 is a prime.

Together with 14311130413, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14311130413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155565205 + 7155565206.

It is an arithmetic number, because the mean of its divisors is an integer number (7155565206).

Almost surely, 2^14311130411 is an apocalyptic number.

14311130411 is a deficient number, since it is larger than the sum of its proper divisors (1).

14311130411 is an equidigital number, since it uses as much as digits as its factorization.

14311130411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 14311130411 its reverse (11403111341), we get a palindrome (25714241752).

The spelling of 14311130411 in words is "fourteen billion, three hundred eleven million, one hundred thirty thousand, four hundred eleven".