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143111551054397 is a prime number
BaseRepresentation
bin100000100010100011000001…
…001010011111001000111101
3200202201022221001111112001112
4200202203001022133020331
5122224214424032220042
61224212312224451405
742100316434620122
oct4042430112371075
9622638831445045
10143111551054397
11416662a4729172
1214073b88a79b65
1361b1490b96a63
14274a8c939a749
1511829d70a9982
hex8228c129f23d

143111551054397 has 2 divisors, whose sum is σ = 143111551054398. Its totient is φ = 143111551054396.

The previous prime is 143111551054391. The next prime is 143111551054411. The reversal of 143111551054397 is 793450155111341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 138656724517081 + 4454826537316 = 11775259^2 + 2110646^2 .

It is a cyclic number.

It is not a de Polignac number, because 143111551054397 - 218 = 143111550792253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143111551054391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71555775527198 + 71555775527199.

It is an arithmetic number, because the mean of its divisors is an integer number (71555775527199).

Almost surely, 2143111551054397 is an apocalyptic number.

It is an amenable number.

143111551054397 is a deficient number, since it is larger than the sum of its proper divisors (1).

143111551054397 is an equidigital number, since it uses as much as digits as its factorization.

143111551054397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1134000, while the sum is 50.

The spelling of 143111551054397 in words is "one hundred forty-three trillion, one hundred eleven billion, five hundred fifty-one million, fifty-four thousand, three hundred ninety-seven".