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14311231041 = 35578564471
BaseRepresentation
bin11010101010000010…
…00000111001000001
31100221101002212022010
431111001000321001
5213302133343131
610324031203133
71014434312442
oct152501007101
940841085263
1014311231041
116084353778
1229349764a9
131470c3c963
1499a9712c9
1558b60eb46
hex355040e41

14311231041 has 8 divisors (see below), whose sum is σ = 19115901504. Its totient is φ = 9523690640.

The previous prime is 14311231027. The next prime is 14311231049. The reversal of 14311231041 is 14013211341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14311231041 - 226 = 14244122177 is a prime.

It is a super-2 number, since 2×143112310412 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14311230999 and 14311231017.

It is not an unprimeable number, because it can be changed into a prime (14311231049) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4280565 + ... + 4283906.

It is an arithmetic number, because the mean of its divisors is an integer number (2389487688).

Almost surely, 214311231041 is an apocalyptic number.

It is an amenable number.

14311231041 is a deficient number, since it is larger than the sum of its proper divisors (4804670463).

14311231041 is an equidigital number, since it uses as much as digits as its factorization.

14311231041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8565031.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 14311231041 its reverse (14013211341), we get a palindrome (28324442382).

The spelling of 14311231041 in words is "fourteen billion, three hundred eleven million, two hundred thirty-one thousand, forty-one".

Divisors: 1 3 557 1671 8564471 25693413 4770410347 14311231041