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143112441209 is a prime number
BaseRepresentation
bin1000010101001000101…
…0101000110101111001
3111200101202022021102112
42011102022220311321
54321043241104314
6145424524142105
713224313451633
oct2052212506571
9450352267375
10143112441209
115576a273301
12238a0097935
1310659654a9a
146cd8b43a53
153ac90c643e
hex21522a8d79

143112441209 has 2 divisors, whose sum is σ = 143112441210. Its totient is φ = 143112441208.

The previous prime is 143112441187. The next prime is 143112441217. The reversal of 143112441209 is 902144211341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100000147984 + 43112293225 = 316228^2 + 207635^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-143112441209 is a prime.

It is a super-3 number, since 3×1431124412093 (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (143112441259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71556220604 + 71556220605.

It is an arithmetic number, because the mean of its divisors is an integer number (71556220605).

Almost surely, 2143112441209 is an apocalyptic number.

It is an amenable number.

143112441209 is a deficient number, since it is larger than the sum of its proper divisors (1).

143112441209 is an equidigital number, since it uses as much as digits as its factorization.

143112441209 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 32.

The spelling of 143112441209 in words is "one hundred forty-three billion, one hundred twelve million, four hundred forty-one thousand, two hundred nine".