Base | Representation |
---|---|
bin | 11010101010000010… |
… | …00101110111100111 |
3 | 1100221101010220021022 |
4 | 31111001011313213 |
5 | 213302140021211 |
6 | 10324031441355 |
7 | 1014434426051 |
oct | 152501056747 |
9 | 40841126238 |
10 | 14311251431 |
11 | 6084368024 |
12 | 293498625b |
13 | 1470c49019 |
14 | 99a9788d1 |
15 | 58b615bdb |
hex | 355045de7 |
14311251431 has 2 divisors, whose sum is σ = 14311251432. Its totient is φ = 14311251430.
The previous prime is 14311251373. The next prime is 14311251469. The reversal of 14311251431 is 13415211341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14311251431 - 210 = 14311250407 is a prime.
It is a super-2 number, since 2×143112514312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 14311251431.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14311251131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155625715 + 7155625716.
It is an arithmetic number, because the mean of its divisors is an integer number (7155625716).
Almost surely, 214311251431 is an apocalyptic number.
14311251431 is a deficient number, since it is larger than the sum of its proper divisors (1).
14311251431 is an equidigital number, since it uses as much as digits as its factorization.
14311251431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1440, while the sum is 26.
Adding to 14311251431 its reverse (13415211341), we get a palindrome (27726462772).
The spelling of 14311251431 in words is "fourteen billion, three hundred eleven million, two hundred fifty-one thousand, four hundred thirty-one".
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