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14311251431 is a prime number
BaseRepresentation
bin11010101010000010…
…00101110111100111
31100221101010220021022
431111001011313213
5213302140021211
610324031441355
71014434426051
oct152501056747
940841126238
1014311251431
116084368024
12293498625b
131470c49019
1499a9788d1
1558b615bdb
hex355045de7

14311251431 has 2 divisors, whose sum is σ = 14311251432. Its totient is φ = 14311251430.

The previous prime is 14311251373. The next prime is 14311251469. The reversal of 14311251431 is 13415211341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14311251431 - 210 = 14311250407 is a prime.

It is a super-2 number, since 2×143112514312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14311251431.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14311251131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155625715 + 7155625716.

It is an arithmetic number, because the mean of its divisors is an integer number (7155625716).

Almost surely, 214311251431 is an apocalyptic number.

14311251431 is a deficient number, since it is larger than the sum of its proper divisors (1).

14311251431 is an equidigital number, since it uses as much as digits as its factorization.

14311251431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1440, while the sum is 26.

Adding to 14311251431 its reverse (13415211341), we get a palindrome (27726462772).

The spelling of 14311251431 in words is "fourteen billion, three hundred eleven million, two hundred fifty-one thousand, four hundred thirty-one".