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1431130307 = 471011032927
BaseRepresentation
bin101010101001101…
…0101000011000011
310200201220221201012
41111103111003003
510412332132212
6354002031135
750315256365
oct12523250303
93621827635
101431130307
11674921422
1233b3484ab
1319a65b089
14d80d6d35
1585993922
hex554d50c3

1431130307 has 16 divisors (see below), whose sum is σ = 1490890752. Its totient is φ = 1372879200.

The previous prime is 1431130291. The next prime is 1431130387. The reversal of 1431130307 is 7030311341.

It is a cyclic number.

It is not a de Polignac number, because 1431130307 - 24 = 1431130291 is a prime.

It is a super-3 number, since 3×14311303073 (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1431130387) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 487478 + ... + 490404.

It is an arithmetic number, because the mean of its divisors is an integer number (93180672).

Almost surely, 21431130307 is an apocalyptic number.

1431130307 is a deficient number, since it is larger than the sum of its proper divisors (59760445).

1431130307 is a wasteful number, since it uses less digits than its factorization.

1431130307 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3178.

The product of its (nonzero) digits is 756, while the sum is 23.

The square root of 1431130307 is about 37830.2829357646. The cubic root of 1431130307 is about 1126.9199300030.

Adding to 1431130307 its reverse (7030311341), we get a palindrome (8461441648).

The spelling of 1431130307 in words is "one billion, four hundred thirty-one million, one hundred thirty thousand, three hundred seven".

Divisors: 1 47 101 103 2927 4747 4841 10403 137569 295627 301481 488941 13894469 14169607 30449581 1431130307