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143113102440 = 233572112212633
BaseRepresentation
bin1000010101001000110…
…1001010010001101000
3111200101210112212110120
42011102031022101220
54321043423234230
6145424550243240
713224322204500
oct2052215122150
9450353485416
10143113102440
115576a685080
12238a0356520
1310659826a49
146cd8c76a00
153ac91a7310
hex215234a468

143113102440 has 192 divisors, whose sum is σ = 544838996160. Its totient is φ = 29737774080.

The previous prime is 143113102427. The next prime is 143113102463. The reversal of 143113102440 is 44201311341.

It is a super-4 number, since 4×1431131024404 (a number of 46 digits) contains 4444 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a self number, because there is not a number n which added to its sum of digits gives 143113102440.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1041637 + ... + 1170996.

It is an arithmetic number, because the mean of its divisors is an integer number (2837703105).

Almost surely, 2143113102440 is an apocalyptic number.

143113102440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

143113102440 is an abundant number, since it is smaller than the sum of its proper divisors (401725893720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

143113102440 is a wasteful number, since it uses less digits than its factorization.

143113102440 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2212672 (or 2212661 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 143113102440 its reverse (44201311341), we get a palindrome (187314413781).

The spelling of 143113102440 in words is "one hundred forty-three billion, one hundred thirteen million, one hundred two thousand, four hundred forty".