1431132400231 has 4 divisors (see below), whose sum is σ = 1431134821512. Its totient is φ = 1431129978952.

The previous prime is 1431132400213. The next prime is 1431132400253. The reversal of 1431132400231 is 1320042311341.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 1431132400231 - 2²³ = 1431124011623 is a prime.

It is a super-2 number, since 2×1431132400231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1431132400196 and 1431132400205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431132400031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 326640 + ... + 1723066.

It is an arithmetic number, because the mean of its divisors is an integer number (357783705378).

Almost surely, 2^{1431132400231} is an apocalyptic number.

1431132400231 is a deficient number, since it is larger than the sum of its proper divisors (2421281).

1431132400231 is a wasteful number, since it uses less digits than its factorization.

1431132400231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2421280.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1431132400231 its reverse (1320042311341), we get a palindrome (2751174711572).

The spelling of 1431132400231 in words is "one trillion, four hundred thirty-one billion, one hundred thirty-two million, four hundred thousand, two hundred thirty-one".