Base | Representation |
---|---|
bin | 10100110100110110001… |
… | …000110110101010001011 |
3 | 12001211000002002120222121 |
4 | 110310312020312222023 |
5 | 141421424343302032 |
6 | 3013241514032111 |
7 | 205252536455263 |
oct | 24646610665213 |
9 | 5054002076877 |
10 | 1431132400267 |
11 | 501a37a26409 |
12 | 1b1443418637 |
13 | a4c557852ab |
14 | 4d3a51c87a3 |
15 | 273613bea97 |
hex | 14d36236a8b |
1431132400267 has 2 divisors, whose sum is σ = 1431132400268. Its totient is φ = 1431132400266.
The previous prime is 1431132400253. The next prime is 1431132400301. The reversal of 1431132400267 is 7620042311341.
It is an a-pointer prime, because the next prime (1431132400301) can be obtained adding 1431132400267 to its sum of digits (34).
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1431132400267 is a prime.
It is not a weakly prime, because it can be changed into another prime (1431132404267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715566200133 + 715566200134.
It is an arithmetic number, because the mean of its divisors is an integer number (715566200134).
Almost surely, 21431132400267 is an apocalyptic number.
1431132400267 is a deficient number, since it is larger than the sum of its proper divisors (1).
1431132400267 is an equidigital number, since it uses as much as digits as its factorization.
1431132400267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 34.
The spelling of 1431132400267 in words is "one trillion, four hundred thirty-one billion, one hundred thirty-two million, four hundred thousand, two hundred sixty-seven".
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