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143113431 = 347704477
BaseRepresentation
bin10001000011110…
…11110011010111
3100222021220201110
420201323303113
5243114112211
622111230103
73355305216
oct1041736327
9328256643
10143113431
117386926a
123bb18333
132385a506
141501507d
15c86dea6
hex887bcd7

143113431 has 4 divisors (see below), whose sum is σ = 190817912. Its totient is φ = 95408952.

The previous prime is 143113393. The next prime is 143113441. The reversal of 143113431 is 134311341.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 143113431 - 26 = 143113367 is a prime.

It is a super-2 number, since 2×1431134312 = 40962908265183522, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143113398 and 143113407.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143113441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23852236 + ... + 23852241.

It is an arithmetic number, because the mean of its divisors is an integer number (47704478).

Almost surely, 2143113431 is an apocalyptic number.

143113431 is a deficient number, since it is larger than the sum of its proper divisors (47704481).

143113431 is an equidigital number, since it uses as much as digits as its factorization.

143113431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47704480.

The product of its digits is 432, while the sum is 21.

The square root of 143113431 is about 11963.0025913230. The cubic root of 143113431 is about 523.0703840385.

Adding to 143113431 its reverse (134311341), we get a palindrome (277424772).

The spelling of 143113431 in words is "one hundred forty-three million, one hundred thirteen thousand, four hundred thirty-one".

Divisors: 1 3 47704477 143113431