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14311401431141 = 53322571837107
BaseRepresentation
bin1101000001000010000111…
…1111111010000001100101
31212200011020011122200202002
43100100201333322001211
53333434222231244031
650234322252255045
73004651604011103
oct320204177720145
955604204580662
1014311401431141
114618482012951
12173178b471485
137ca736bcccc9
143769658d8c73
1519c4144e3ccb
hexd0421ffa065

14311401431141 has 8 divisors (see below), whose sum is σ = 14581490495904. Its totient is φ = 14041314685840.

The previous prime is 14311401431123. The next prime is 14311401431143. The reversal of 14311401431141 is 14113410411341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14311401431141 - 214 = 14311401414757 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14311401431143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16677710 + ... + 17514816.

It is an arithmetic number, because the mean of its divisors is an integer number (1822686311988).

Almost surely, 214311401431141 is an apocalyptic number.

It is an amenable number.

14311401431141 is a deficient number, since it is larger than the sum of its proper divisors (270089064763).

14311401431141 is an equidigital number, since it uses as much as digits as its factorization.

14311401431141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1159731.

The product of its (nonzero) digits is 2304, while the sum is 29.

Adding to 14311401431141 its reverse (14113410411341), we get a palindrome (28424811842482).

The spelling of 14311401431141 in words is "fourteen trillion, three hundred eleven billion, four hundred one million, four hundred thirty-one thousand, one hundred forty-one".

Divisors: 1 53 322571 837107 17096263 44366671 270026442097 14311401431141