Base | Representation |
---|---|
bin | 11010101010000011… |
… | …01101100100000101 |
3 | 1100221101110011022011 |
4 | 31111001231210011 |
5 | 213302210222041 |
6 | 10324035134221 |
7 | 1014436004062 |
oct | 152501554405 |
9 | 40841404264 |
10 | 14311414021 |
11 | 60844691a3 |
12 | 2934a44371 |
13 | 1470ca5028 |
14 | 99a9bbc69 |
15 | 58b648e81 |
hex | 35506d905 |
14311414021 has 4 divisors (see below), whose sum is σ = 14311940544. Its totient is φ = 14310887500.
The previous prime is 14311414009. The next prime is 14311414063. The reversal of 14311414021 is 12041411341.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 14311414021 - 217 = 14311282949 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14311413983 and 14311414001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14311414321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220135 + ... + 277636.
It is an arithmetic number, because the mean of its divisors is an integer number (3577985136).
Almost surely, 214311414021 is an apocalyptic number.
It is an amenable number.
14311414021 is a deficient number, since it is larger than the sum of its proper divisors (526523).
14311414021 is an equidigital number, since it uses as much as digits as its factorization.
14311414021 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 526522.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 14311414021 its reverse (12041411341), we get a palindrome (26352825362).
The spelling of 14311414021 in words is "fourteen billion, three hundred eleven million, four hundred fourteen thousand, twenty-one".
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