Base | Representation |
---|---|
bin | 11010101010000011… |
… | …01110010100100011 |
3 | 1100221101110022120001 |
4 | 31111001232110203 |
5 | 213302210321443 |
6 | 10324035200431 |
7 | 1014436016113 |
oct | 152501562443 |
9 | 40841408501 |
10 | 14311417123 |
11 | 6084470563 |
12 | 2934a46117 |
13 | 1470ca6573 |
14 | 99a9bd043 |
15 | 58b649d4d |
hex | 35506e523 |
14311417123 has 2 divisors, whose sum is σ = 14311417124. Its totient is φ = 14311417122.
The previous prime is 14311417067. The next prime is 14311417181. The reversal of 14311417123 is 32171411341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14311417123 - 229 = 13774546211 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14311417091 and 14311417100.
It is not a weakly prime, because it can be changed into another prime (14311417723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155708561 + 7155708562.
It is an arithmetic number, because the mean of its divisors is an integer number (7155708562).
Almost surely, 214311417123 is an apocalyptic number.
14311417123 is a deficient number, since it is larger than the sum of its proper divisors (1).
14311417123 is an equidigital number, since it uses as much as digits as its factorization.
14311417123 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2016, while the sum is 28.
Adding to 14311417123 its reverse (32171411341), we get a palindrome (46482828464).
The spelling of 14311417123 in words is "fourteen billion, three hundred eleven million, four hundred seventeen thousand, one hundred twenty-three".
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