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14311424553 = 347041101411
BaseRepresentation
bin11010101010000011…
…10000001000101001
31100221101110200202020
431111001300020221
5213302211041203
610324035255053
71014436046556
oct152501601051
940841420666
1014311424553
1160844760a8
122934a4a489
131470ca9a6a
1499a9c1a2d
1558b64c153
hex355070229

14311424553 has 8 divisors (see below), whose sum is σ = 19082493216. Its totient is φ = 9540652800.

The previous prime is 14311424539. The next prime is 14311424581. The reversal of 14311424553 is 35542411341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14311424553 - 212 = 14311420457 is a prime.

It is a super-2 number, since 2×143114245532 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14311424593) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 90418 + ... + 191828.

It is an arithmetic number, because the mean of its divisors is an integer number (2385311652).

Almost surely, 214311424553 is an apocalyptic number.

It is an amenable number.

14311424553 is a deficient number, since it is larger than the sum of its proper divisors (4771068663).

14311424553 is a wasteful number, since it uses less digits than its factorization.

14311424553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 148455.

The product of its digits is 28800, while the sum is 33.

Adding to 14311424553 its reverse (35542411341), we get a palindrome (49853835894).

The spelling of 14311424553 in words is "fourteen billion, three hundred eleven million, four hundred twenty-four thousand, five hundred fifty-three".

Divisors: 1 3 47041 101411 141123 304233 4770474851 14311424553