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1431203132431 is a prime number
BaseRepresentation
bin10100110100111010010…
…110101011010000001111
312001211012000012011021101
4110310322112223100033
5141422101000214211
63013252522043531
7205254355621432
oct24647226532017
95054160164241
101431203132431
11501a73947546
121b14630495a7
13a4c6731c147
144d3b075b819
15273676e25c1
hex14d3a5ab40f

1431203132431 has 2 divisors, whose sum is σ = 1431203132432. Its totient is φ = 1431203132430.

The previous prime is 1431203132399. The next prime is 1431203132467. The reversal of 1431203132431 is 1342313021341.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1431203132431 - 25 = 1431203132399 is a prime.

It is a super-2 number, since 2×14312031324312 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1431203132431.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1431203135431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715601566215 + 715601566216.

It is an arithmetic number, because the mean of its divisors is an integer number (715601566216).

Almost surely, 21431203132431 is an apocalyptic number.

1431203132431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431203132431 is an equidigital number, since it uses as much as digits as its factorization.

1431203132431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1431203132431 its reverse (1342313021341), we get a palindrome (2773516153772).

The spelling of 1431203132431 in words is "one trillion, four hundred thirty-one billion, two hundred three million, one hundred thirty-two thousand, four hundred thirty-one".