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1431214141 = 7204459163
BaseRepresentation
bin101010101001110…
…1001100000111101
310200202002012201011
41111103221200331
510412342323031
6354003515221
750316055660
oct12523514075
93622065634
101431214141
11674979405
1233b388b11
1319a68a296
14d81196d7
15859ad6b1
hex554e983d

1431214141 has 4 divisors (see below), whose sum is σ = 1635673312. Its totient is φ = 1226754972.

The previous prime is 1431214133. The next prime is 1431214151. The reversal of 1431214141 is 1414121341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1431214141 - 23 = 1431214133 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431214111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102229575 + ... + 102229588.

It is an arithmetic number, because the mean of its divisors is an integer number (408918328).

Almost surely, 21431214141 is an apocalyptic number.

It is an amenable number.

1431214141 is a deficient number, since it is larger than the sum of its proper divisors (204459171).

1431214141 is an equidigital number, since it uses as much as digits as its factorization.

1431214141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 204459170.

The product of its digits is 384, while the sum is 22.

The square root of 1431214141 is about 37831.3909472015. The cubic root of 1431214141 is about 1126.9419341397.

Adding to 1431214141 its reverse (1414121341), we get a palindrome (2845335482).

The spelling of 1431214141 in words is "one billion, four hundred thirty-one million, two hundred fourteen thousand, one hundred forty-one".

Divisors: 1 7 204459163 1431214141