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143121464413 is a prime number
BaseRepresentation
bin1000010101001010110…
…1000011110001011101
3111200102101021200221021
42011102231003301131
54321103043330123
6145425445404141
713224453242434
oct2052255036135
9450371250837
10143121464413
11557743765a4
12238a3109651
131065b493b65
146cda01211b
153ac9ca9c5d
hex2152b43c5d

143121464413 has 2 divisors, whose sum is σ = 143121464414. Its totient is φ = 143121464412.

The previous prime is 143121464389. The next prime is 143121464429. The reversal of 143121464413 is 314464121341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 135952963524 + 7168500889 = 368718^2 + 84667^2 .

It is an emirp because it is prime and its reverse (314464121341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143121464413 - 225 = 143087909981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143121465413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71560732206 + 71560732207.

It is an arithmetic number, because the mean of its divisors is an integer number (71560732207).

Almost surely, 2143121464413 is an apocalyptic number.

It is an amenable number.

143121464413 is a deficient number, since it is larger than the sum of its proper divisors (1).

143121464413 is an equidigital number, since it uses as much as digits as its factorization.

143121464413 is an evil number, because the sum of its binary digits is even.

The product of its digits is 27648, while the sum is 34.

Adding to 143121464413 its reverse (314464121341), we get a palindrome (457585585754).

The spelling of 143121464413 in words is "one hundred forty-three billion, one hundred twenty-one million, four hundred sixty-four thousand, four hundred thirteen".