1431221323333 has 4 divisors (see below), whose sum is σ = 1431436972780. Its totient is φ = 1431005673888.

The previous prime is 1431221323321. The next prime is 1431221323381. The reversal of 1431221323333 is 3333231221341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 230494089604 + 1200727233729 = 480098^2 + 1095777^2 .

It is a cyclic number.

It is not a de Polignac number, because 1431221323333 - 2⁹ = 1431221322821 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1431221323295 and 1431221323304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1432221323333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107814768 + ... + 107828041.

It is an arithmetic number, because the mean of its divisors is an integer number (357859243195).

Almost surely, 2^{1431221323333} is an apocalyptic number.

It is an amenable number.

1431221323333 is a deficient number, since it is larger than the sum of its proper divisors (215649447).

1431221323333 is an equidigital number, since it uses as much as digits as its factorization.

1431221323333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 215649446.

The product of its digits is 23328, while the sum is 31.

Adding to 1431221323333 its reverse (3333231221341), we get a palindrome (4764452544674).

The spelling of 1431221323333 in words is "one trillion, four hundred thirty-one billion, two hundred twenty-one million, three hundred twenty-three thousand, three hundred thirty-three".