14312234041 has 6 divisors (see below), whose sum is σ = 16648925370. Its totient is φ = 12267629136.

The previous prime is 14312234009. The next prime is 14312234047. The reversal of 14312234041 is 14043221341.

14312234041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 10164874041 + 4147360000 = 100821^2 + 64400^2 .

It is not a de Polignac number, because 14312234041 - 2⁵ = 14312234009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14312233997 and 14312234015.

It is not an unprimeable number, because it can be changed into a prime (14312234047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 146043156 + ... + 146043253.

It is an arithmetic number, because the mean of its divisors is an integer number (2774820895).

Almost surely, 2^14312234041 is an apocalyptic number.

It is an amenable number.

14312234041 is a deficient number, since it is larger than the sum of its proper divisors (2336691329).

14312234041 is an equidigital number, since it uses as much as digits as its factorization.

14312234041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 292086423 (or 292086416 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14312234041 its reverse (14043221341), we get a palindrome (28355455382).

The spelling of 14312234041 in words is "fourteen billion, three hundred twelve million, two hundred thirty-four thousand, forty-one".