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1431230026234 = 2715615013117
BaseRepresentation
bin10100110100111011111…
…101010001000111111010
312001211020212210111122011
4110310323331101013322
5141422124341314414
63013255322320134
7205255133332141
oct24647375210772
95054225714564
101431230026234
11501a88046228
121b147005904a
13a4c6ca77338
144d3b415c758
1527369c55dc4
hex14d3bf511fa

1431230026234 has 4 divisors (see below), whose sum is σ = 2146845039354. Its totient is φ = 715615013116.

The previous prime is 1431230026229. The next prime is 1431230026243. The reversal of 1431230026234 is 4326200321341.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1209109164025 + 222120862209 = 1099595^2 + 471297^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1431230026196 and 1431230026205.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 357807506557 + ... + 357807506560.

Almost surely, 21431230026234 is an apocalyptic number.

1431230026234 is a deficient number, since it is larger than the sum of its proper divisors (715615013120).

1431230026234 is an equidigital number, since it uses as much as digits as its factorization.

1431230026234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 715615013119.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1431230026234 its reverse (4326200321341), we get a palindrome (5757430347575).

The spelling of 1431230026234 in words is "one trillion, four hundred thirty-one billion, two hundred thirty million, twenty-six thousand, two hundred thirty-four".

Divisors: 1 2 715615013117 1431230026234