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143123600539957 is a prime number
BaseRepresentation
bin100000100010101110001111…
…010111101000000100110101
3200202202111000210201210211111
4200202232033113220010311
5122224414113214234312
61224222024023035021
742101224146556462
oct4042561727500465
9622674023653744
10143123600539957
1141670418309aa4
121407639029ba71
1361b266136677b
14274b30d7ba669
151182e8ed528a7
hex822b8f5e8135

143123600539957 has 2 divisors, whose sum is σ = 143123600539958. Its totient is φ = 143123600539956.

The previous prime is 143123600539949. The next prime is 143123600539991. The reversal of 143123600539957 is 759935006321341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108127845590116 + 34995754949841 = 10398454^2 + 5915721^2 .

It is a cyclic number.

It is not a de Polignac number, because 143123600539957 - 23 = 143123600539949 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143123600039957) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71561800269978 + 71561800269979.

It is an arithmetic number, because the mean of its divisors is an integer number (71561800269979).

Almost surely, 2143123600539957 is an apocalyptic number.

It is an amenable number.

143123600539957 is a deficient number, since it is larger than the sum of its proper divisors (1).

143123600539957 is an equidigital number, since it uses as much as digits as its factorization.

143123600539957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18370800, while the sum is 58.

The spelling of 143123600539957 in words is "one hundred forty-three trillion, one hundred twenty-three billion, six hundred million, five hundred thirty-nine thousand, nine hundred fifty-seven".