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143124040259149 is a prime number
BaseRepresentation
bin100000100010101110101001…
…100101000001011001001101
3200202202112011110010212011111
4200202232221211001121031
5122224421013301243044
61224222135411452021
742101241066246565
oct4042565145013115
9622675143125144
10143124040259149
1141670623543594
12140764935b7011
1361b27014a3b41
14274b351d5dda5
151182eb875eb34
hex822ba994164d

143124040259149 has 2 divisors, whose sum is σ = 143124040259150. Its totient is φ = 143124040259148.

The previous prime is 143124040259141. The next prime is 143124040259191. The reversal of 143124040259149 is 941952040421341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113967474558025 + 29156565701124 = 10675555^2 + 5399682^2 .

It is a cyclic number.

It is not a de Polignac number, because 143124040259149 - 23 = 143124040259141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143124040259141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71562020129574 + 71562020129575.

It is an arithmetic number, because the mean of its divisors is an integer number (71562020129575).

Almost surely, 2143124040259149 is an apocalyptic number.

It is an amenable number.

143124040259149 is a deficient number, since it is larger than the sum of its proper divisors (1).

143124040259149 is an equidigital number, since it uses as much as digits as its factorization.

143124040259149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1244160, while the sum is 49.

The spelling of 143124040259149 in words is "one hundred forty-three trillion, one hundred twenty-four billion, forty million, two hundred fifty-nine thousand, one hundred forty-nine".