Base | Representation |
---|---|
bin | 100000100010101110101001… |
… | …100101000001101011101010 |
3 | 200202202112011110010220210020 |
4 | 200202232221211001223222 |
5 | 122224421013301312310 |
6 | 1224222135411501310 |
7 | 42101241066253203 |
oct | 4042565145015352 |
9 | 622675143126706 |
10 | 143124040260330 |
11 | 41670623544468 |
12 | 140764935b7836 |
13 | 61b27014a453c |
14 | 274b351d605aa |
15 | 1182eb8760170 |
hex | 822ba9941aea |
143124040260330 has 32 divisors (see below), whose sum is σ = 343498068244224. Its totient is φ = 38166369445056.
The previous prime is 143124040260323. The next prime is 143124040260391. The reversal of 143124040260330 is 33062040421341.
It is a junction number, because it is equal to n+sod(n) for n = 143124040260291 and 143124040260300.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34209112 + ... + 38164268.
It is an arithmetic number, because the mean of its divisors is an integer number (10734314632632).
Almost surely, 2143124040260330 is an apocalyptic number.
143124040260330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
143124040260330 is an abundant number, since it is smaller than the sum of its proper divisors (200374027983894).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
143124040260330 is a wasteful number, since it uses less digits than its factorization.
143124040260330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5161390.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 143124040260330 its reverse (33062040421341), we get a palindrome (176186080681671).
The spelling of 143124040260330 in words is "one hundred forty-three trillion, one hundred twenty-four billion, forty million, two hundred sixty thousand, three hundred thirty".
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