Base | Representation |
---|---|
bin | 11010101010001011… |
… | …00101100111010011 |
3 | 1100221110100210000022 |
4 | 31111011211213103 |
5 | 213302440230120 |
6 | 10324113014055 |
7 | 1014450435161 |
oct | 152505454723 |
9 | 40843323008 |
10 | 14312430035 |
11 | 6084aa2582 |
12 | 293525432b |
13 | 147126c617 |
14 | 99aba4231 |
15 | 58b79a025 |
hex | 3551659d3 |
14312430035 has 8 divisors (see below), whose sum is σ = 17177086800. Its totient is φ = 11448496864.
The previous prime is 14312429983. The next prime is 14312430043. The reversal of 14312430035 is 53003421341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14312430035 - 220 = 14311381459 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14312429986 and 14312430013.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 136385 + ... + 217314.
It is an arithmetic number, because the mean of its divisors is an integer number (2147135850).
Almost surely, 214312430035 is an apocalyptic number.
14312430035 is a deficient number, since it is larger than the sum of its proper divisors (2864656765).
14312430035 is an equidigital number, since it uses as much as digits as its factorization.
14312430035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 361797.
The product of its (nonzero) digits is 4320, while the sum is 26.
Adding to 14312430035 its reverse (53003421341), we get a palindrome (67315851376).
The spelling of 14312430035 in words is "fourteen billion, three hundred twelve million, four hundred thirty thousand, thirty-five".
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