Base | Representation |
---|---|
bin | 1101000001000101111101… |
… | …0100000101101100000001 |
3 | 1212200020212212100002222202 |
4 | 3100101133110011230001 |
5 | 3333443324103210334 |
6 | 50235012321042545 |
7 | 3005016234556634 |
oct | 320213724055401 |
9 | 55606785302882 |
10 | 14312430131969 |
11 | 461895a75a022 |
12 | 1731a17a86455 |
13 | 7ca86c078a18 |
14 | 376a22397c1b |
15 | 19c47499417e |
hex | d045f505b01 |
14312430131969 has 2 divisors, whose sum is σ = 14312430131970. Its totient is φ = 14312430131968.
The previous prime is 14312430131933. The next prime is 14312430132019. The reversal of 14312430131969 is 96913103421341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7632583120369 + 6679847011600 = 2762713^2 + 2584540^2 .
It is a cyclic number.
It is not a de Polignac number, because 14312430131969 - 216 = 14312430066433 is a prime.
It is a super-2 number, since 2×143124301319692 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14312430130969) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156215065984 + 7156215065985.
It is an arithmetic number, because the mean of its divisors is an integer number (7156215065985).
Almost surely, 214312430131969 is an apocalyptic number.
It is an amenable number.
14312430131969 is a deficient number, since it is larger than the sum of its proper divisors (1).
14312430131969 is an equidigital number, since it uses as much as digits as its factorization.
14312430131969 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 419904, while the sum is 47.
The spelling of 14312430131969 in words is "fourteen trillion, three hundred twelve billion, four hundred thirty million, one hundred thirty-one thousand, nine hundred sixty-nine".
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