Base | Representation |
---|---|
bin | 1101000001000101111101… |
… | …0100000101101100110011 |
3 | 1212200020212212100010001121 |
4 | 3100101133110011230303 |
5 | 3333443324103211034 |
6 | 50235012321043111 |
7 | 3005016234560035 |
oct | 320213724055463 |
9 | 55606785303047 |
10 | 14312430132019 |
11 | 461895a75a068 |
12 | 1731a17a86497 |
13 | 7ca86c078a56 |
14 | 376a22397c55 |
15 | 19c4749941b4 |
hex | d045f505b33 |
14312430132019 has 2 divisors, whose sum is σ = 14312430132020. Its totient is φ = 14312430132018.
The previous prime is 14312430131969. The next prime is 14312430132137. The reversal of 14312430132019 is 91023103421341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14312430132019 - 231 = 14310282648371 is a prime.
It is a super-2 number, since 2×143124301320192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14312430132419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156215066009 + 7156215066010.
It is an arithmetic number, because the mean of its divisors is an integer number (7156215066010).
Almost surely, 214312430132019 is an apocalyptic number.
14312430132019 is a deficient number, since it is larger than the sum of its proper divisors (1).
14312430132019 is an equidigital number, since it uses as much as digits as its factorization.
14312430132019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 14312430132019 in words is "fourteen trillion, three hundred twelve billion, four hundred thirty million, one hundred thirty-two thousand, nineteen".
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