Base | Representation |
---|---|
bin | 100000100010101110111001… |
… | …001011101001001110100001 |
3 | 200202202112211200201210202021 |
4 | 200202232321023221032201 |
5 | 122224422032310321032 |
6 | 1224222221402421441 |
7 | 42101250425335132 |
oct | 4042567113511641 |
9 | 622675750653667 |
10 | 143124302042017 |
11 | 4167074829496a |
12 | 14076547201881 |
13 | 61b27437b074a |
14 | 274b378a25c89 |
15 | 1182ed1720097 |
hex | 822bb92e93a1 |
143124302042017 has 2 divisors, whose sum is σ = 143124302042018. Its totient is φ = 143124302042016.
The previous prime is 143124302042003. The next prime is 143124302042023. The reversal of 143124302042017 is 710240203421341.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 132797597678656 + 10326704363361 = 11523784^2 + 3213519^2 .
It is a cyclic number.
It is not a de Polignac number, because 143124302042017 - 227 = 143124167824289 is a prime.
It is not a weakly prime, because it can be changed into another prime (143124302042077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71562151021008 + 71562151021009.
It is an arithmetic number, because the mean of its divisors is an integer number (71562151021009).
Almost surely, 2143124302042017 is an apocalyptic number.
It is an amenable number.
143124302042017 is a deficient number, since it is larger than the sum of its proper divisors (1).
143124302042017 is an equidigital number, since it uses as much as digits as its factorization.
143124302042017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32256, while the sum is 34.
Adding to 143124302042017 its reverse (710240203421341), we get a palindrome (853364505463358).
The spelling of 143124302042017 in words is "one hundred forty-three trillion, one hundred twenty-four billion, three hundred two million, forty-two thousand, seventeen".
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