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14312453114023 is a prime number
BaseRepresentation
bin1101000001000110000010…
…1011110000100010100111
31212200020221110120201102221
43100101200223300202213
53333443400444122043
650235014501413211
73005016634116001
oct320214053604247
955606843521387
1014312453114023
114618971726859
121731a2370a207
137ca873a6457c
14376a2545b371
1519c4769d38ed
hexd0460af08a7

14312453114023 has 2 divisors, whose sum is σ = 14312453114024. Its totient is φ = 14312453114022.

The previous prime is 14312453113939. The next prime is 14312453114111. The reversal of 14312453114023 is 32041135421341.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14312453114023 - 237 = 14175014160551 is a prime.

It is a super-2 number, since 2×143124531140232 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14312453114023.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14312453111023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156226557011 + 7156226557012.

It is an arithmetic number, because the mean of its divisors is an integer number (7156226557012).

Almost surely, 214312453114023 is an apocalyptic number.

14312453114023 is a deficient number, since it is larger than the sum of its proper divisors (1).

14312453114023 is an equidigital number, since it uses as much as digits as its factorization.

14312453114023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 14312453114023 its reverse (32041135421341), we get a palindrome (46353588535364).

The spelling of 14312453114023 in words is "fourteen trillion, three hundred twelve billion, four hundred fifty-three million, one hundred fourteen thousand, twenty-three".