14312453114132 has 12 divisors (see below), whose sum is σ = 25420625680800. Its totient is φ = 7049417205336.

The previous prime is 14312453114111. The next prime is 14312453114147. The reversal of 14312453114132 is 23141135421341.

It is a super-2 number, since 2×14312453114132² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14312453114092 and 14312453114101.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26702337632 + ... + 26702338167.

It is an arithmetic number, because the mean of its divisors is an integer number (2118385473400).

Almost surely, 2^{14312453114132} is an apocalyptic number.

It is an amenable number.

14312453114132 is a deficient number, since it is larger than the sum of its proper divisors (11108172566668).

14312453114132 is a wasteful number, since it uses less digits than its factorization.

14312453114132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53404675870 (or 53404675868 counting only the distinct ones).

The product of its digits is 34560, while the sum is 35.

Adding to 14312453114132 its reverse (23141135421341), we get a palindrome (37453588535473).

The spelling of 14312453114132 in words is "fourteen trillion, three hundred twelve billion, four hundred fifty-three million, one hundred fourteen thousand, one hundred thirty-two".