14312542511231 has 2 divisors, whose sum is σ = 14312542511232. Its totient is φ = 14312542511230.

The previous prime is 14312542511221. The next prime is 14312542511243. The reversal of 14312542511231 is 13211524521341.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14312542511231 - 2¹⁰ = 14312542510207 is a prime.

It is a super-2 number, since 2×14312542511231² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14312542511191 and 14312542511200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14312542511221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156271255615 + 7156271255616.

It is an arithmetic number, because the mean of its divisors is an integer number (7156271255616).

Almost surely, 2^{14312542511231} is an apocalyptic number.

14312542511231 is a deficient number, since it is larger than the sum of its proper divisors (1).

14312542511231 is an equidigital number, since it uses as much as digits as its factorization.

14312542511231 is an evil number, because the sum of its binary digits is even.

The product of its digits is 28800, while the sum is 35.

The spelling of 14312542511231 in words is "fourteen trillion, three hundred twelve billion, five hundred forty-two million, five hundred eleven thousand, two hundred thirty-one".